(x^3-2x-4)(x+2)=0

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Solution for (x^3-2x-4)(x+2)=0 equation: 


Simplifying
(x3 + -2x + -4)(x + 2) = 0

Reorder the terms:
(-4 + -2x + x3)(x + 2) = 0

Reorder the terms:
(-4 + -2x + x3)(2 + x) = 0

Multiply (-4 + -2x + x3) * (2 + x)
(-4(2 + x) + -2x * (2 + x) + x3(2 + x)) = 0
((2 * -4 + x * -4) + -2x * (2 + x) + x3(2 + x)) = 0
((-8 + -4x) + -2x * (2 + x) + x3(2 + x)) = 0
(-8 + -4x + (2 * -2x + x * -2x) + x3(2 + x)) = 0
(-8 + -4x + (-4x + -2x2) + x3(2 + x)) = 0
(-8 + -4x + -4x + -2x2 + (2 * x3 + x * x3)) = 0
(-8 + -4x + -4x + -2x2 + (2x3 + x4)) = 0

Combine like terms: -4x + -4x = -8x
(-8 + -8x + -2x2 + 2x3 + x4) = 0

Solving
-8 + -8x + -2x2 + 2x3 + x4 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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